5/x-6/1/x^2-36+5/x+6

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Solution for 5/x-6/1/x^2-36+5/x+6 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x+5/x-((6/1)/(x^2))-36+6 = 0

5/x+5/x-6*x^-2-36+6 = 0

10*x^-1-6*x^-2-30 = 0

t_1 = x^-1

10*t_1^1-6*t_1^2-30 = 0

10*t_1-6*t_1^2-30 = 0

DELTA = 10^2-(-30*(-6)*4)

DELTA = -620

DELTA < 0

x belongs to the empty set

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